10x^2-64x/21=2

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Solution for 10x^2-64x/21=2 equation: 


x in (-oo:+oo)

10*x^2-((64*x)/21) = 2 // - 2

10*x^2-((64*x)/21)-2 = 0

10*x^2+(-64/21)*x-2 = 0

10*x^2-64/21*x-2 = 0

DELTA = (-64/21)^2-(-2*4*10)

DELTA = 39376/441

DELTA > 0

x = ((39376/441)^(1/2)+64/21)/(2*10) or x = (64/21-(39376/441)^(1/2))/(2*10)

x = ((39376/441)^(1/2)+64/21)/20 or x = (64/21-(39376/441)^(1/2))/20

x in { (64/21-(39376/441)^(1/2))/20, ((39376/441)^(1/2)+64/21)/20 }

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